Find the divisor

**Lesson 1:** Find x

a) \(x + 12 = 36\) | b) \(x \times 6 = 30\) |

c) \(x-25=15\) | d) \(x:7=5\) |

e) \(80-x=30\) | g) \(42:x=7\) |

**Solution guide **

- To find the term, we subtract the other term from the sum.
- To find a factor, we divide the product by the other factor.
- To find the number to be subtracted, we use the difference of addition and subtraction.
- To find the divisor we take the merchant by the divisor.
- To find a minus number, we subtract the difference from the subtracted number.
- To find the divisor, we divide the divisor by the quotient.

a) \(x+12=36\) \(\begin{array}{l} |
b) \(x \times 6 = 30\) \(\begin{array}{l} |

c) \(x-25=15\) \(\begin{array}{l} |
d) \(x:7=5\) \(\begin{array}{l} |

e) \(80-x=30\) \(\begin{array}{l} |
g) \(42:x=7\) \(\begin{array}{l} |

**Lesson 2:** Calculate

a) \(\underline { \times \begin{array}{*{20}{c}}

{35}\\

{\,\,\,2}

\end{array}} \) \(\underline { \times \begin{array}{*{20}{c}}

{26}\\

{\,\,\,4}

\end{array}} \) \(\underline { \times \begin{array}{*{20}{c}}

{32}\\

{\,\,\,6}

\end{array}} \) \(\underline { \times \begin{array}{*{20}{c}}

{20}\\

{\,\,\,7}

\end{array}} \)

b) \(\left. {\begin{array}{*{20}{c}}

{sixty four}\\

{}

\end{array}} \right|\begin{array}{*{20}{c}}

2\\

\hline

{}

\end{array}\) \(\left. {\begin{array}{*{20}{c}}

{80}\\

{}

\end{array}} \right|\begin{array}{*{20}{c}}

4\\

\hline

{}

\end{array}\) \(\left. {\begin{array}{*{20}{c}}

{99}\\

{}

\end{array}} \right|\begin{array}{*{20}{c}}

3\\

\hline

{}

\end{array}\) \(\left. {\begin{array}{*{20}{c}}

{sixty four}\\

{}

\end{array}} \right|\begin{array}{*{77}{c}}

7\\

\hline

{}

\end{array}\)

**Solution guide**

- Perform multiplication in order from right to left.
- Perform division in order from left to right.

a)

\(\begin{array}{l}

\underline { \times \begin{array}{*{20}{c}}

{35}\\

{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} 2}

\end{array}} \\

\,\,\,\,\,70

\end{array}\) \(\begin{array}{l}

\underline { \times \begin{array}{*{20}{c}}

{26}\\

{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} 4}

\end{array}} \\

\,\,\,104

\end{array}\) \(\begin{array}{l}

\underline { \times \begin{array}{*{20}{c}}

{32}\\

{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} 6}

\end{array}} \\

\,\,\,192

\end{array}\) \(\begin{array}{l}

\underline { \times \begin{array}{*{20}{c}}

{20}\\

{{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} 7}

\end{array}} \\

\,\,\,140

\end{array}\)

b)

\(\begin{array}{l}

\left. {\underline {\begin{array}{*{20}{c}}

{sixty four}\\

6

\end{array}} } \right|\begin{array}{*{20}{c}}

2\\

\hline

{32}

\end{array}\\

\underline {\begin{array}{*{20}{c}}

{04}\\

{\,\,4}

\end{array}} \\

\,\,\,\,0

\end{array}\) \(\begin{array}{l}

\left. {\underline {\begin{array}{*{20}{c}}

{80}\\

8

\end{array}} } \right|\begin{array}{*{20}{c}}

4\\

\hline

{20}

\end{array}\\

\underline {\begin{array}{*{20}{c}}

{00}\\

{\,\,\,0}

\end{array}} \\

\,\,\,\,0

\end{array}\) \(\begin{array}{l}

\left. {\underline {\begin{array}{*{20}{c}}

{99}\\

9

\end{array}} } \right|\begin{array}{*{20}{c}}

3\\

\hline

{33}

\end{array}\\

\underline {\begin{array}{*{20}{c}}

{09}\\

{\,\,9}

\end{array}} \\

\,\,\,\,0

\end{array}\) \(\begin{array}{l}

\left. {\underline {\begin{array}{*{20}{c}}

{77}\\

7

\end{array}} } \right|\begin{array}{*{20}{c}}

7\\

\hline

{11}

\end{array}\\

\underline {\begin{array}{*{20}{c}}

{07}\\

{\,\,7}

\end{array}} \\

\,\,\,\,0

\end{array}\)

**Lesson 3:** There are 36 liters of oil in the tank. After use, the amount of oil remaining in the tank is equal to \(\frac{1}{3}\) the amount of oil already available. How many liters of oil are left in the tank?

**Solution guide **

*Summary *

To find the solution, we divide the number of liters of oil in the tank by 3.

**Solution **

In the remaining tank, the number of liters of oil is:

36 : 3 = 12 (liters)

Answer: 12 liters.

**Lesson 4:** Circle the word in front of the correct answer

A. 1 hour 50 minutes

B. 1 hour 25 minutes

C. 2 hours 25 minutes

D. 5 hours 10 minutes

**Solution guide**

Determine where the hour and minute hands are pointing, and then read the time of the watch.

**Solution **

The watch is having a short hand pointing between number 1 and number 2; long needle points to number 5.

So the clock is showing 1 hour 25 minutes.

Circle the letter B: 1 hour 25 minutes.

.

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